Question 67430: (x^2-2x-15)(x-4)=0 solve by finding roots
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! (x^2-2x-15)(x-4)=0 solve by finding roots
Note that x^2-2x-15 has factors of (x-5)(x+3). How did I know this?? I determined that it has factors by inspection and by knowing that when a quadratic (Ax^2+Bx+C=0) has the A coefficient equal to 1, then the B coefficient is equal to the sum of the factors of the C coefficient, if it is factorable and in this case (-5)(+3) works.
So we have:
(x-5)(x+3)(x-4)=0
x=5
x=-3
x=4
Hope this helps-------ptaylor
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