SOLUTION: Show that 7ac+14ab+28a=7a(c+2b+4). Use values for a,b,c, and d to justify your answer?
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Question 66846This question is from textbook Glencoe Pre-Algebra
: Show that 7ac+14ab+28a=7a(c+2b+4). Use values for a,b,c, and d to justify your answer?
This question is from textbook Glencoe Pre-Algebra
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
There is no d.
set a=2, n=-3 & c=1
7(2*1)+14(2*-3)+28*2=7*2(1+2*-3+4)
7*2+14*-6+56=14(1-6+4)
14-84+56=14(-1)
-14=-14
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