SOLUTION: A list contains 11 consecutive integers. If x is the smallest integer and y is the greatest integer on the list, and 16x^-2=y^-2. Find the value of (x+y)?

Question 662445: A list contains 11 consecutive integers. If x is the smallest integer and y is the greatest integer on the list, and 16x^-2=y^-2. Find the value of (x+y)?
Answer by Edwin McCravy(20062) (Show Source): You can put this solution on YOUR website!

The list of 11 consists of

1.  x
2.  x+1
3.  x+2
4.  x+3
5.  x+4
6.  x+5
7.  x+6
8.  x+7
9.  x+8
10. x+9
11. x+10

So x is the the smallest and y = x+10 is the largest.

16x^-2 = y^-2

Using the definition of negative exponents:

 = 

Cross-multiply

16y� = x�

Since y = x+10, substitute x+10 for y

16(x+10)� = x�

Solve that for x, then find y from y = x+10, 

Then it'll be easy to find (x+y)

If you have trouble, you may ask me in the thank-you note.

Edwin

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