SOLUTION: SQRT(X)+ SQRT(Y)= SQRT(72), then find the possible values of X+Y.
Algebra.Com
Question 662442: SQRT(X)+ SQRT(Y)= SQRT(72), then find the possible values of X+Y.
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
Divide both sides by SQRT
SQRT(x)/SQRT + SQRT(y)/SQRT = SQRT(72)/SQRT
x+y=72
x = 72-y
y = 72-x
RELATED QUESTIONS
find an equation of the line that bisects the obtuse angles formed by the lines with... (answered by solver91311)
If x = sqrt 3 + sqrt 2 over sqrt 3 - sqrt 2 and y=1, then the value of x-y over
x-3y is (answered by Edwin McCravy)
Rationalize the denominator:... (answered by jim_thompson5910)
Find the difference if (y-x) if {{{6x + 5y + sqrt(6x + 5y) =72}}} and {{{3x - 4y +... (answered by math_tutor2020)
Find the domain:
Y= sqrt.... (answered by MathLover1,ikleyn)
8=sqrt(x)sqrt(x)sqrt(x)sqrt(x...), find the value of... (answered by RAY100)
Find the smallest possible value:
{{{sqrt(x^2+y^2)}}} + {{{sqrt((x-1)^2+y^2)}}} +... (answered by ikleyn)
Find the smallest possible value sqrt(x^2 + y^2) + sqrt((x-1)^2+y^2)) + sqrt x^2+(y-1)^2 (answered by ikleyn)
find the (nth) derivative of. y= x^n * sqrt(x) (answered by MathLover1)