Hi, there-- Problem: Find the center (h, k) and the radius r of the circleAnswer: We want to rearrange this equation into the form (x-h)^2 +(y-k)^2 = r^2. Then we can read the center point and the radius right off the equation. Divide every term in the equation by 3, so that the x-squared and y-squared terms have a coefficient of 1. Add 5/3 to both sides of the equation. Complete the square for the x terms by adding a constant. To make a perfect square trinomial find half the coefficient of the x-term and square it. Half of 7/3 is 7/6. Th square of 7/6 is 49/36. Add this to both sides of the equation. Repeat this process for the y-terms. Write each trinomial in factored form. Sum up the constants on the right side. The square root of 158/36 is because the square root of 36 is 6. THe final equation is The center of the circle is the point (h,k)=(-7/6, 7/6) The radius of the circle is Hope this helps! Feel free to email if my explanation is unclear or you have additional questions. Mrs.Figgy math.in.the.vortex@gmail.com