SOLUTION: Just looking at this problem I am not able to put it in standard form. P^2+15p+25=6p+5 I'm supposed to be solving for the root of each equation. It's just not making sense h

Question 66068This question is from textbook beginning algebra
: Just looking at this problem I am not able to put it in standard form.
P^2+15p+25=6p+5
I'm supposed to be solving for the root of each equation.
It's just not making sense how I should write this.
Thank you This question is from textbook beginning algebra

Answer by algebrapro18(249) (Show Source): You can put this solution on YOUR website!
Well to solve a quadratic equation by factoring you need to do the following:
1)Get everything on the same side of the squared term.
2)Factor the quadratic equation
a)Multiply the a and c terms together where a and c are coefficients.
b)Factor that number and see what factors add to the b term.
*Note: You might end up haveing to take the negative of both factors to get
them to add right.
3)re-write the equation as a product of its factors.
4)Set each factor equal to 0 and solve

P^2+15p+25=6p+5
p^2+15p-6p+25-5=0
p^2+9p+20=0

a = 1, b = 9, c = 20

a * c = 1*20 = 20

factors of 20 are:
1 and 20
2 and 10
4 and 5

4 * 5 = 20
4 + 5 = 9

p^2+9p+20=0
(p+4)(p+5)=0

now set each equation to 0 and solve.

p + 4 = 0
p = -4

p + 5 = 0
p = -5

so your roots are x = -4 and x = -5.
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