SOLUTION: Solve for X:
2(x-5)^2=3
I know the first step I believe is to multiply the 2 towards the x and the 5:
2*x = 2x
2*5 = 10
(2x - 10)^2 = 3
The next step is to figure out what
Algebra.Com
Question 65704: Solve for X:
2(x-5)^2=3
I know the first step I believe is to multiply the 2 towards the x and the 5:
2*x = 2x
2*5 = 10
(2x - 10)^2 = 3
The next step is to figure out what X is correct?
2(x) - 10^2 = 3
Gosh I am lost on this step, could someone please give me a hand, thank you
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
FIRST YOU MUST RESOLVE THE ITEMS WITHIN THE ( )
(X-5)^2=X^2-10X+25 NOW MULTIPLY THIS BY 2
2(X^2-10X+25)=2X^2-20X+50 NOW SET THIS =3
2X^2-20X+50=3 NOW SUBTRACT 3 FROM BOTH SIDES
2X^2-20X+50-3=0
2X^2-20X+47=0 THIS EQUATION DOESN'T FACTOR NORMALLY THUS WE NEED THE QUADRATIC EQUATION TO FIND THE X VALUES THUS
X=(-B+-SQRT[B^2-4AC])/2A
X=(20+-SQRT[400-4*2*47])/2*2
X=(20+-SQRT[400-376])/4
X=(20+-SQRT[24])/4
X=(20+-4.899)/4
X=(20+4.899)/4
X=6.22 SOLUTION
X=(20-4.899)/4
X=15.101/4
X=3.77 SOLUTION
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