SOLUTION: Divide the fraction: 6p-18 / 3p-9 --------------- 9p / p^2+2p The first step is to invert the second fraction I believe: 6p-18 / p^2+2p ---------------- 9p

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Question 65476: Divide the fraction:
6p-18 / 3p-9
---------------
9p / p^2+2p
The first step is to invert the second fraction I believe:
6p-18 / p^2+2p
----------------
9p 3p-9
The next step is to cancel out I think:
3 goes in to 6, 9, and 18
The last fraction has no cancel outs leaving the equation looking like this:
2p-6 / p^2+2p
---------------
3p / 3p-9
From here I become preety lost. Is there any hope for me in figuring this problem out? I would be happy with a good break down for future reference as well so I could really figure them out. Thank you in advance for the great help!
Answer by stanbon(48535) (Show Source):
You can put this solution on YOUR website!
Divide the fraction:
6p-18 / 3p-9
---------------
9p / p^2+2p
==================
Rewrite as follows:
=[6(p-3)/3(p-3)] / [9p/p(p+2)]
Cancel where you can to get:
=2/[9/(p+2)]
Invert the denominator and multiply to get:
=(2/9)(p+2)
Cheers,
stan H.