SOLUTION: Please help factor the polynomial completely 2w^2+6w-108 the answer is 2(w-6)(w+9) how do you arrive at this?

SOLUTION: Please help factor the polynomial completely 2w^2+6w-108 the answer is 2(w-6)(w+9) how do you arrive at this?

Algebra.Com

Question 64916: Please help factor the polynomial completely
2w^2+6w-108 the answer is 2(w-6)(w+9) how do you arrive at this?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
FIRST YOU DIVIDE ALL TERMS BY 2
2(W^2+3W-54) NOW YOU FACTOR THE REMAINING QUADRATIC EQUATION
2(X-6)(X+9) YOU FIND 2 NUMBERS THAT HAVE A PRODUCT OF -54=(9*-6) & THE DIFFERENCE IS 3=(9-6)
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