SOLUTION: solve by factoring show check each answer here is the problem 2x^2+3x=2 heres how I solved the problem 2x^2+3x-2=0

Question 636433: solve by factoring show check each answer
here is the problem 2x^2+3x=2
heres how I solved the problem
2x^2+3x-2=0
2x^2=4x-x-2=0
2x(x+2)-(x+2)=0
(x+2)(2x-1)=0
x=2 please show me how to check each answer
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
solve by factoring show check each answer
here is the problem 2x^2+3x=2
heres how I solved the problem
2x^2+3x-2=0
2x^2=4x-x-2=0
2x(x+2)-(x+2)=0
(x+2)(2x-1)=0
x=2 please show me how to check each answer

First, your solution, is incorrect. Since x + 2 = 0, then
Second, there�s another solution, as
Since x = - 2, we will substitute - 2 for x into the original equation to determine if this value for x makes the equation true

x = - 2
becomes:

2(4) - 6 = 2
. This is true.

The same concept applies to the check for the 2nd solution:

Send comments and �thank-yous� to �D� at MathMadEzy@aol.com
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