SOLUTION: Solve the equation: 4-5(y+2)=2(y-1)-7y-4
I keep attempting to solve for y and I keep getting -2. When I checked my answer using the widget on this website, it said I should be g
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Question 635544: Solve the equation: 4-5(y+2)=2(y-1)-7y-4
I keep attempting to solve for y and I keep getting -2. When I checked my answer using the widget on this website, it said I should be getting 0. I don't understand the steps they're using.
I distributed the 4 and -5 to (y+2) and the 2 to (y-1). I combined the like terms on both sides of the equal sign, then I moved my y to the left and my constants to the right. What am I doing wrong?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I think the key to what you are doing wrong is in your statement "I distributed the 4 and -5 to (y + 2)..." The 4 has nothing to do with the (y + 2) factor.
\ =\ 2(y\ -\ 1)\ -\ 7y\ -\ 4)
Which is true for any real value of 
, hence the solution set is:
John
My calculator said it, I believe it, that settles it
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