Hi,

each side of square is lengthened by 2inches

Area of New Square = (s+2)^2 = 36

 s^2 +4x + 4 = 36

 s^2 + 4x - 32 = 0

(s+8)(s -4) = 0

      s = 4in  (throwing out negative solution for unit measure



and...

 

Answer by graphmatics(170)   (Show Source): You can put this solution on YOUR website!
 Let x be the length of sides of the original square. For the new square we have

(x+2)(x+2)=36

x^2+4x-32=0

(x-4)(x+8)=0

x-4=0, x+8=0

x=4, x=-8

x=4 is the length of sides of the original square. 

RELATED QUESTIONS

Solve the problem.

Each side of a square is lengthened by 2 inches. The area of this... (answered by josgarithmetic)

Each side of a square is lengthened by 3 inches. The area of this new, larger square is... (answered by fcabanski)

each side of a square is lengthened by 1 inch. the area of this new, larger square is 100  (answered by checkley79)

each side of a a square is lengthened by 5 inches. the area of this new larger square is... (answered by solver91311)

If each side of a square is lengthened by 4m, the area becomes 49m^2.Find the length of a  (answered by Fombitz)

If each side of a square are lengthened by by 5 cm, the area becomes 144 cm ^2. Find the... (answered by ewatrrr)

if each of the sides of a square is lengthened by 4 m, the area becomes 49 m². find the... (answered by mangeshpjoshi)

If each of the sides of a square is lengthened by 4m, the area becomes {{{ 49m^2}}}. Find  (answered by rfer)

The area of a square is 36 square feet. If each side is lengthened by 4 feet, how could... (answered by ankor@dixie-net.com)