SOLUTION: I have some equations in the following format (finding the nth term of an algebraic expression) ( n ) a^(n-(r-1)) * b^(r-1) r-1 I don't understand what the (n & r-1) term

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Question 628135: I have some equations in the following format (finding the nth term of an algebraic expression)
( n ) a^(n-(r-1)) * b^(r-1)
r-1
I don't understand what the (n & r-1) terms in the parenthesis at the beginning of the expression are. From the solution, it suggests that the first term ends up resolving to a division of factorials such as:
(6! / ((6-3)! * 3!)) where n=6 and r=4...
I just dont understand how they got from the first form to the factorial form.

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


I think what you are looking at is (read: "n choose r - 1") which is the number of combinations of things taken at a time. Such as, how many ways can I choose from 10 different books on a shelf if I take them 3 at a time and I don't care what order the three are in when I get them in my hand?

In general, is calculated by . Hence, your is exactly correct given and .

Here's the logic: Let's say you have 6 things and want to choose 3 of them. There are 6 ways to choose the first one, then since you didn't replace the first one you chose, there are 5 ways to choose the second one for each one of the 6 ways to choose the first one. Then there are 4 ways to choose the third one for each of the 30 ways to pick the first two, which works out to which comes from . But that number is too large by a factor of the number of ways to arrange the three things in your hand, namely , and that is where the other denominator factor comes from.

You might want to compare this to the number of permutations of things taken at a time. With permutations, order matters. Such as you have 20 people in your club and you want to know how many different ways you can select a President, Secretary, and Treasurer. Here order matters because Suzy being the president is a different outcome than Suzy being the Secretary, for example. Permutations are calculated . See the difference?

By the way, this is also the th coefficient (counting from zero) of the binomial expansion of and the th element of the th row of Pascal's Triangle.

John

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