Can you help solve this equation? 3x^2+9bx=ax +3ab So far I've tried 3x^2+9bx-ax-3ab=0 -(a-3x)(3b+x)=0 I am to solve for x Thanks Here is another (harder) way to do it using the quadratic formula: 3x² + 9bx = ax + 3ab Get all terms on the left 3x² + 9bx - ax - 3ab = 0 Factor x out of the middle two terms 3x² + x(9b - a) - 3ab = 0 Rewrite the middle term x(9b - a) as (9b - a)x 3x² + (9b - a)x - 3ab = 0 Now this is in the form: Ax² + Bx + C = 0 where A = 3, B = (9b - a) and C = -3ab Notice that I used capital letters A, B, and C to prevent confusion with the small letters a and b in your equation: Use the quadratic formula: ______ -B ± ÖB²-4AC x = ————————————— 2A __________________ -(9b-a) ± Ö(9b-a)²-4(3)(-3ab) x = ——————————————————————————————— 2(3) ____________ -(9b-a) ± Ö(9b-a)²+36ab x = ———————————————————————————— 6 _________________ -(9b-a) ± Ö(9b-a)(9b-a)+36ab x = ——————————————————————————————— 6 _________________ -(9b-a) ± Ö81b²-18ab+a²+36ab x = ——————————————————————————————— 6 ____________ -(9b-a) ± Ö81b²+18ab+a² x = —————————————————————————— 6 ____________ -(9b-a) ± Ö(9b+a)(9b+a) x = —————————————————————————— 6 _______ -(9b-a) ± Ö(9b+a)² x = ————————————————————— 6 -(9b-a) ± (9b+a) x = ————————————————————— 6 Using the +, -(9b-a) + (9b+a) x = ————————————————————— 6 -9b + a + 9b + a x = —————————————————— 6 2a x = ———— 6 a x = ——— 3 Using the -, -(9b-a) - (9b+a) x = ————————————————————— 6 -9b + a - 9b - a x = —————————————————— 6 -18b x = —————— 6 x = -3b So the two solutions are a x = ——— and x = -3b 3 Edwin