SOLUTION: -3/(x+5) - -2/(x+4) + (-1-3)/(x^2+9x+20)=A/B
A=
B=
(x^2-(9x+5)/(x^2+1x+6) + (3x^2-6-6x)/(-6-1x-x^2)=A/B
A=
B=
Solve (x-1)/9 greater than or equal to (x-5)/15
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Question 617799: -3/(x+5) - -2/(x+4) + (-1-3)/(x^2+9x+20)=A/B
A=
B=
(x^2-(9x+5)/(x^2+1x+6) + (3x^2-6-6x)/(-6-1x-x^2)=A/B
A=
B=
Solve (x-1)/9 greater than or equal to (x-5)/15+5/45
Solve the equation 1/(x+2)-1/(x+3)=1/2
The selling price of a textbook is $150.00. If the markup is 20% of the bookstore's cost, what is the bookstore's cost of the textbook?
a) Write an equation to model the problem. Use x to represent the number.
Answer:
b) Solve the equation to find the bookstore's cost. (Note: Your answer should be in the form $ddd.cc.)
Answer:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The LCD is (x\ +\ 3))
So
\ -\ 2(x\ +\ 2)}{2(x\ +\ 2)(x\ +\ 3)}\ =\ \frac{(x\ +\ 2)(x\ +\ 3)}{2(x\ +\ 2)(x\ +\ 3)})
Multiply by
\ -\ 2(x\ +\ 2)\ =\ (x\ +\ 2)(x\ +\ 3))
Expand, simplify, and solve the resulting quadratic.
John
My calculator said it, I believe it, that settles it
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