SOLUTION: f(x)= x^-2x+8\x+4

Question 61023: f(x)= x^-2x+8\x+4
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
f(x)=(x^2-2x+8)/(x+4)
You didn't give us instructions.
x cannot = -4 has to be stipulated, because the original function is undefined when it's denominator equals 0
The domain therefore is {x|x cannot=-4}<--set builder notation
There is a vertical asymptote at x=-4
The degree of the numerator is higher than the denominator, so there is no horizontal asymptote.
The degree of the numerator is exactly 1 more than the denominator, so there is a slant asymtote you can get through long division of y=x-6.
If you plot a few points on both sides of x=-4 you get this graph.

If you had something else in mind, let me know.
Happy Calculating!!!
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