SOLUTION: Solve square root of 2x+3- square root of x+1=1

Question 606659: Solve square root of 2x+3- square root of x+1=1
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve square root of 2x+3- square root of x+1=1
:

Square both sides, you have to FOIL the right side
2x + 3 =
:
2x + 3 = x + 2 +
:
2x - x + 3 - 2 =
:
(x + 1) =
:
Square both sides, FOIL the left side
:
x^2 + 2x + 1 = 4(x+1)
x^2 + 2x + 1 = 4x + 4
x^2 + 2x - 4x + 1 - 4 = 0
x^2 - 2x - 3 = 0
Factors to
(x-3)(x+1) = 0
Two solutions
x = 3
x = -1
;
We have to check both solutions in the original equation
x = -1 will not work, it would give us a neg value inside the radical
Try x = 3
; looks OK, x=3 is our solution
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