SOLUTION: how do you factor (x-3)^2-2(x-3)-8? Factoring trinomials

Question 601564: how do you factor (x-3)^2-2(x-3)-8? Factoring trinomials
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(x-3)^2-2(x-3)-8?
---
Let w = x-3
----
Rewrite your problem:
w^2 - 2w - 8
----
Factor:
(w-4)(w+2)
----
Substitute back to the "x" form:
(x-3-4)(x-3+2)
----
= (x-7)(x-1)
===============
Cheers,
Stan H.
===============
RELATED QUESTIONS
How do you factor 5xy^2-9xy+4x? factoring... (answered by josmiceli)

x^4-20x^3+96x^2 could you help me solve this problem on factoring... (answered by jim_thompson5910)

How do you factor trinomials that are equal to something such as:x^2-x+56=17x (answered by Earlsdon)

how do you factor {{{3x^2y-11xy-8y}}}? Factoring... (answered by Rcmathtutor)

factoring trinomials... (answered by stanbon)

x^2+10x+24=0 Factoring... (answered by jim_thompson5910)

Factoring Trinomials... (answered by jim_thompson5910)

Factoring trinomials, 2/x^2+2x-3 Thanks for the... (answered by gonzo)

Can you please show me how to factor these two trinomials? 4x^2 + 16x - 8 x^2 -... (answered by MathLover1)