SOLUTION: 1. If X^2+x+1=0 ,then what is the value of (x^3+1/x^3)^3 ? 2. If X^X+Y=Y^3 and Y^X+Y=X^6*Y^3 ,where X and Y are natural numbers then what is the value of Y^X ?

Question 596132: 1. If X^2+x+1=0 ,then what is the value of (x^3+1/x^3)^3 ?
2. If X^X+Y=Y^3 and Y^X+Y=X^6*Y^3 ,where X and Y are natural numbers then what is the value of Y^X ?

Answer by Edwin McCravy(20055) (Show Source): You can put this solution on YOUR website!

I already answered 1

http://www.algebra.com/algebra/homework/equations/Equations.faq.question.596131.html 

2. If X^X+Y=Y^3 and Y^X+Y=X^6*Y^3 ,where X and Y are natural numbers then what
is the value of Y^X ?

There are no natural number solutions to that, so I assumed you must
have left off the necessary parentheses to show where the exponents start and
end.  So I rewrote it as this, which does have 2 natural number solutions:  

2. If X^(X+Y)=Y^3 and Y^(X+Y)=X^6*Y^3 ,where X and Y are natural numbers then
what is the value of Y^X ?

or in superscripted exponent notation:

2. If  =  and  =  ,where X and
Y are natural numbers then what is the value of Y^X ?

There are two solutions to that  (x,y) = (1,1) and (x,y) = (2,4)

So for the first solution  =  = 1
And for the second  =  = 16

Edwin

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