# SOLUTION: Could someone please help me with this problem? Jo Ellen found that if the product of a number and 5 is increased by 20, the result is 28 less than the opposite of the number. Wh

Algebra ->  Algebra  -> Equations -> SOLUTION: Could someone please help me with this problem? Jo Ellen found that if the product of a number and 5 is increased by 20, the result is 28 less than the opposite of the number. Wh      Log On

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 Question 581028: Could someone please help me with this problem? Jo Ellen found that if the product of a number and 5 is increased by 20, the result is 28 less than the opposite of the number. What is the number? Answer by ankor@dixie-net.com(15622)   (Show Source): You can put this solution on YOUR website!Jo Ellen found that if the product of a number and 5 is increased by 20, the result is 28 less than the opposite of the number. What is the number? : let x = "the number" then -x = "the opposite of the number" : Just write an equation for what it says 5x + 20 = -x - 28 5x + x = -28 - 20 6x = -48 x = -48/6 x = -8, it's opposite would be +8 ; : Check this solution in the original equation 5(-8) + 20 = +8 - 28 -40 + 20 = -20 -20 = -20