SOLUTION: Find the equation of the line perpendicular to 2x+3y=12 and passes thru the point (-4,6)
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Question 576464: Find the equation of the line perpendicular to 2x+3y=12 and passes thru the point (-4,6)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Since in the given equation the 
and 
terms are on the same side of the equals sign, take the opposite of the coefficent on and divide by the coefficient on to find the slope of the line represented by the given equation.
Use the point-slope form of an equation of a line to write the desired equation:
 )
where )
are the coordinates of the given point and 
is the calculated slope.
Put the derived equation into either Standard or Slope-Intercept Form as desired by your teacher/professor/instructor.0
However, please note that you cannot write "the" equation of any line. You can only write "an" equation of a line. In the first place, you could just substitute the values in the point-slope form and have an equation of the desired line, or you could solve for 
to put it into slope-intercept form, or you could rearrange it into standard form, namely 
. Furthermore, for a given 
, 
, and 
, 
where 
describes a set of equations with an infinite number of elements, each of which graphs to the same line in 
.
John
My calculator said it, I believe it, that settles it
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