SOLUTION: 8(t-3) + 4t= 6(2t+1)-10

Question 57424: 8(t-3) + 4t= 6(2t+1)-10
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
8(t-3) + 4t= 6(2t+1)-10 First simplify both sides following the order of operation. (PEMDAS, let me know if you don't know what that is.)
8t+8(-3)+4t=6(2t)+6(1)-10
8t-24+4t=12t+6-10
12t-24=12t-4 Now try to get your t's on one side of the = sign, within the rules of algebra.
-12t+12t-24=-12t+12t-4
-24=-4 Your variables were eliminated and -24 does not = -4, therefore there is no solution.
Happy Calculating!!!
RELATED QUESTIONS
1/2t-6+8(t-9+7)=4t*3-5+2+3/4t (answered by jim_thompson5910)

(t� - 2t - 3)/(t� - 1) � (3t - 3)/(t� - 4t +... (answered by jim_thompson5910)

3/8-1/4t=1/2t-3/4 (answered by rahman)

Solve: (2t + 1)^3 = (2t + 1) My solution: (2t + 1)^3 / (2t + 1) = (2t + 1) / (2t +... (answered by richwmiller)

h(t)=-2t^2+4t+6 (answered by greenestamps)

Subtract (7 + t − 5t^2 + 2t^3) − (1 + 2t − 4t^2 + 5t^3) (answered by mananth)

(-2st^2t)(t^2)^3(s^4t) (answered by MathLover1)

Simplify: t^2 - 2t -3 / t^2 - 1 (multiplied by) 3t - 3 / t^2 - 4t +... (answered by mananth)

1.)3s+2-5s+8= 2.)4t+5r-6+2t-8r=... (answered by rchill)