SOLUTION: Find four consecutive integers such that twice the first subtracted from the sum of the other three integers equals 16.

Question 571549: Find four consecutive integers such that twice the first subtracted from the sum of the other three integers equals 16.
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find four consecutive integers such that twice the first subtracted from the sum of the other three integers equals 16.
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1st: x-2
2nd: x-1
3rd: x
4th: x+1
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Equation:
sum - 2(x-2) = 16
4x-2 - 2x+4 = 16
2x + 2 = 16
x = 7
---
1st: 5
2nd: 6
3rd: 7
4th: 8
Checking:
26-10 = 16
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Cheers,
Stan H.
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
Find four consecutive integers such that twice the first subtracted from the sum of the other three integers equals 16.

Let the first integer be F

Then other three are: F + 1, F + 2, and F + 3

Since twice the first subtracted from the sum of the other three integers equals 16, we therefore have: (F + 1 + F + 2 + F + 3) - 2F = 16

3F + 6 - 2F = 16

F + 6 = 16

F, or first integer = 16 - 6, or 10

The four integers are:

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Check
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2 times first = 2(10), or 20

Sum of other three = 11 + 12 + 13, or 36

36 - 20 = 16 (TRUE)

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