SOLUTION: For the equation 3x^2+xy+2y^2=0, which of the following is true? (a) x=y+√y^2-4(3)(2y^2) (over/divided)2(3) (b) x=-y+√y^2-4(3)(2y^2) (over/divided)2(3) (c) x=-

Question 568618: For the equation 3x^2+xy+2y^2=0, which of the following is true?
(a) x=y+√y^2-4(3)(2y^2) (over/divided)2(3)
(b) x=-y+√y^2-4(3)(2y^2) (over/divided)2(3)
(c) x=-y+√x^2-4(3)(2y^2) (over/divided)2(3)
(d) x=-y+√y^2-4(3)(3x^2) (over/divided)2(3)
Thank you so much in advance!

Answer by AnlytcPhil(1806) (Show Source): You can put this solution on YOUR website!

3x� + xy + 2y� = 0

(3)x� + (y)x + (2y�) = 0

a=3, b=y, c = 2y�





The 2 solutions are 

 and 

The first one is the same as choice (b)

Edwin

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SOLUTION: For the equation 3x^2+xy+2y^2=0, which of the following is true? (a) x=y+&#8730;y^2-4(3)(2y^2) (over/divided)2(3) (b) x=-y+&#8730;y^2-4(3)(2y^2) (over/divided)2(3) (c) x=-

SOLUTION: For the equation 3x^2+xy+2y^2=0, which of the following is true? (a) x=y+√y^2-4(3)(2y^2) (over/divided)2(3) (b) x=-y+√y^2-4(3)(2y^2) (over/divided)2(3) (c) x=-