SOLUTION: How do you identify the vertex and exis of symmetry of an equation?

Question 561174: How do you identify the vertex and exis of symmetry of an equation?
Found 2 solutions by nyc_function, stanbon:
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Do you have a sample equation I can help you with in this regard?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you identify the vertex and axis of symmetry of an equation?
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Vertex occurs at (-b/(2a) , f(-b/(2a))
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The axis of symmetry is x = -b/(2a) if the parabola opens up or down.
The axis of symmetry is y = -b/(2a) if the parabola opens right or left.
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Cheers,
Stan H.
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