SOLUTION: The equation that describes the path of a rocket after it is shot in the air is {{{h=80t-16t^2}}}, where h is the height, in feet, above the ground after t seconds. After how man

Question 553801: The equation that describes the path of a rocket after it is shot in the air is , where h is the height, in feet, above the ground after t seconds. After how many seconds will the rocket be at a height of 96 feet?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Set h = 96 and solve the quadratic equation for t.
Subtract 96 from both sides and rearrange.
Factor 16 to ease calculations.
Factor the trinomial.

Apply the zero product rule:
or so:
or
You have two solutions for this problem which was to be expected because quadratics have two solutions.
At t = 2 seconds, the rocket reaches a height of 96 feet on the way up.
At t = 3 seconds, it will pass the 96-foot level on the way down.
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