SOLUTION: Find the number of sides of a convex polygon if the measures of its interior angles have a sum of 6840�

Question 550746: Find the number of sides of a convex polygon if the measures of its interior angles have a sum of 6840�
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
The sum of the measures of the interior angles of a convex polygon with n sides is (n-2)180�.
An easy way to understand and remember that is imagining a point in the interior of the polygon connected to all of the vertices forming n triangles.
The sum of all the angles in those triangles would be n(180�).
If you subtract the 2(180�)=360� corresponding to the angles at the point inside the polygon, you get the sum of the measures of the interior angles as (n-2)180�.
6840�/180�=38=n-2 --> n=40
The number of sides of that polygon is 40.
I am not going to draw it.
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