SOLUTION: Add (x^2+2x-3)+(3x^3+6x^2+9x-5)

Algebra.Com
Question 549794: Add

(x^2+2x-3)+(3x^3+6x^2+9x-5)

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
(x^2+2x-3)+(3x^3+6x^2+9x-5)


x^2+2x-3+3x^3+6x^2+9x-5


3x^3+(x^2+6x^2)+(2x+9x)+(-3-5)


3x^3+7x^2+11x-8


So (x^2+2x-3)+(3x^3+6x^2+9x-5) = 3x^3+7x^2+11x-8

RELATED QUESTIONS

(x^2+2x-3)+(3x^3+6x^2+9x-5) (answered by jim_thompson5910)
Fully factor P(x)= 2x^3... (answered by Alan3354)
perform the indicated operation and simplify your answer: x^2+6x+5 over 3x^2-9x-12... (answered by greenestamps)
I need help please 6x+5=3x+6 5x+8=x+5 9x+1=3x-4 2x-3=6x-4 3/4x+2=1/4x-9 (answered by checkley75)
(9x^4+2x^3-x+5)+(9x^3-3x^2+8x+3)-(7x^4-x+12) (answered by CubeyThePenguin)
(((x+1/x+4 + x-3/x+5 = (2x^2+6x+11)/(x^2 +... (answered by edjones)
Solve by removing the inner parentheses first and working outward.... (answered by haileytucki)
add... (answered by algebrahouse.com)
Divide 9x^3-6x^2+12x-5 by... (answered by josgarithmetic)