# SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+4

Algebra ->  Algebra  -> Equations -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+4      Log On

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 Algebra: Equations Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Equations Question 547063: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+4Answer by lwsshak3(6513)   (Show Source): You can put this solution on YOUR website!Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. f(x)=-2x^2+2x+4 ** Standard form of equation for a parabola which opens downwards: y=-A(x-h)^2+k, (h,k) being the (x,y) coordinates of the vertex f(x)=-2x^2+2x+4 complete the square f(x)=-2(x^2-x+1/4)+4+1/2 f(x)=-2(x-1/2)^2+9/2 A=-2 vertex(1/2,9/2) line or axis of symmetry: x=1/2 maximum value: 9/2 see graph below as a visual check on the above: