SOLUTION: Find three consecutive odd numbers such that three times the smallest number is the same as nine more than twice the largest.

Question 546938: Find three consecutive odd numbers such that three times the smallest number is the same as nine more than twice the largest.
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Let
First odd integer = x+1
Second odd integer = x+3
Third odd integer = x+5
Given
Three times the smallest number is the same as nine more than twice the largest
3(x+1)=2(x+5)+9
3x+3=2x+10+9
3x+3=2x+10+9
3x-2x=19-3
x=16

First odd integer = x+1 = 16+1=17
Second odd integer = x+3=16+3=19
Third odd integer = x+5=16+5=21

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