SOLUTION: I have an exam in just a little more than an hour. I am going over my review for the exam and there are 2 problems that I have the answers for, because they have given us that but

Question 535794: I have an exam in just a little more than an hour. I am going over my review for the exam and there are 2 problems that I have the answers for, because they have given us that but I need to know how to go about solving the probelems. Anyone's help is greatly appreciated!!!
_x+4_ = _x+10___
x-3 x+2
Not sure if this makes any sense... I am not sure how to type this up.. It is fractions. x+4 is over x-3 and then it is = in the middle with x+10 above x+2.
The other one that I am struggling with is this
__5__ + _3__ = 1
3x x
This is the same it is a fraction but instead of it being a fraction at the end it is an equals sign with a 1. Thanks so much!
Found 2 solutions by ankor@dixie-net.com, Earlsdon:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
=
Cross multiply
(x+4)(x+2) = (x-3)(x+10)
FOIL
x^2 + 2x + 4x + 8 = x^2 + 10x - 3x - 30
x^2 + 6x + 8 = x^2 + 7x - 30
Combine the x's on the left, combine the numbers on the right
x^2 - x^2 + 6x - 7x = -30 - 8
-x = -38
which is
x = 38
Check this in the original problem
:
+ = 1
Multiply by 3x
3x* + 3x* = 3x(1)
Cancel the denominators, and you have:
5 + 3(3) = 3x
14 = 3x
x = 14/3
x = 4
:
:
Check this in the original, you can use 4.67 to do this on a calc, it should be very close to 1
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve:
1) Cross-multiply.
Perform the indicated multiplication.
Subtract from both sides.
Subtract 6x from both sides.
Add 30 to both sides.
or
---------------------------------------
2) Use the common denominator of 3x to add the two fractions.

Multiply boh sides by 3x.
Divide both sides by 3.
or
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