SOLUTION: 4/(x+2)-3/(x-1)=5/((x-1)(x+2)) need steps

Algebra.Com
Question 535015: 4/(x+2)-3/(x-1)=5/((x-1)(x+2))
need steps

Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!
Given to solve:
.

.
Just as a matter of interest, note that x cannot equal either +1 or -2. Why? Because either of those two values would make a denominator become zero, and division by zero is not permitted by the rules of algebra.
.
On to the problem. To get rid of the denominators let's multiply the entire problem (all three terms of the terms ... two terms on the left side and one term on the right side) by (x-1)*(x+2). This multiplication leads to:
.

.
Then in each term cancel out the factor in the numerator with the same factor in the denominator:
.

.
And you are left with no denominators:
.

.
Do the distributed multiplications for each of the two terms on the left side:
.

.
Combine the two x terms (4x and - 3x) and the two constants (-4 and - 6) on the left side and you get:
.

.
Eliminate the constant on the left side by adding +10 to both sides:
.

.
And that's the answer to this problem.
.
Hope this helps you to understand how to do this. You can often make fractional problems easier by multiplying by the least common denominator to get rid of all the denominators so that you can work it more like a conventional algebra problem.
.

RELATED QUESTIONS

hi i need help with quadratic equations and i need steps please 1)(x-6)(x-4)=0... (answered by MathLover1)
(1/4)(x+5) = (1/2) (2x-3) need help (answered by Fombitz)
what is (x+1)(x+5)=(x+2)(x+3) i need help with.. 1.x^2-1 2.x^2-9... (answered by stanbon)
I need the steps for solving... (answered by elima)
{{{((x-1)/(x^2-5x+6))+((x)/(x-2))=((2)/(x-3))}}} I need steps and answer!... (answered by ankor@dixie-net.com,MathTherapy)
2/3(x+5)-1=4-x (answered by rfer,MathTherapy)
(x-1)(x-2)(x-3)<0... (answered by lwsshak3)
x/2-3/4=1/3 Please show steps? (answered by oberobic)
(x-2)/3 + (y+1)/5 = please show... (answered by jim_thompson5910)