SOLUTION: 78+3c+12-c+4, 1+p+5+p=2 please explain clearly and show the steps

Question 529236: 78+3c+12-c+4, 1+p+5+p=2 please explain clearly and show the steps
Answer by boilpoil(127) (Show Source): You can put this solution on YOUR website!
I think you wish to simplify the first one and solve the second one.
1)
78+3c+12-c+4
78+12+4+3c-c --- Reordering the terms: Numbers with numbers, unknowns with unknowns
94+2c --- Calculating: 78+12+4 = 94, 3c-(1)c = 2c
This would be your final answer
2)
1+p+5+p=2
1+5+p+p=2 --- Reordering the terms: Numbers with numbers, unknowns with unknowns
6+2p=2 --- Calculating: 1+5=6, p+p=2p
2p=2-6 --- Moved the term +6 to the right hand side and becomes -6
2p=-4 --- Calculating: 2-6 = -4
--- Dividing both sides by 2, and erases the denominator of '2p'
p=-2
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