SOLUTION: Question 3:
Solve for x:
4x + 4/2 = 3(x + 1) – 2
x =
Question 4:
Solve for x. Enter this answer as a fraction:
6x – 3 = 2x – (4 – 3)/3
x =
Q
Algebra.Com
Question 52708: Question 3:
Solve for x:
4x + 4/2 = 3(x + 1) – 2
x =
Question 4:
Solve for x. Enter this answer as a fraction:
6x – 3 = 2x – (4 – 3)/3
x =
Question 5:
Solve for x:
x/2 + x/3 = (3x + 2)/4
x =
Question 6:
Solve for x:
-4x – 2 = -6 – 2x
x =
Answer by rchill(405) (Show Source): You can put this solution on YOUR website!
I'll solve one of them for you and you can do the other three as the process stays the same for all four. To solve for x, you need to isolate x on either side of the '=' sign. So, for question 3, let's eliminate that nasty denominator of 2 on the left side of the equation by multiplying both sides by 2. Doing that gives us . Expanding the right side yields , or . Subtracting 6x on both sides yields . Now subtract 4 from both sides and get . Dividing both sides by 2 yields . To check this answer, substitute -1 in for x in the original equation, thusly: . Expanding the equation gives us which simplifies to . Because this is a true statement, our answer of x=-1 is correct. You can do the other three problems by repeating the process.
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