SOLUTION: y=5x^2-30x+47
Find the vertex and the axis of symmetry for the parabola with the given equation.
Algebra.Com
Question 519031: y=5x^2-30x+47
Find the vertex and the axis of symmetry for the parabola with the given equation.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
For any quadratic function of the form:
The coordinates of the vertex are found by:
 = f\left(\frac{-b}{2a}\right))
And the equation of the axis of symmetry is:
Which is to say:
Just plug in the numbers and do the arithmetic.
John
My calculator said it, I believe it, that settles it
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