SOLUTION: How do you solve:
3A+2F=240
2A+1F=140
1.5A+.5F=100
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Question 51369: How do you solve:
3A+2F=240
2A+1F=140
1.5A+.5F=100
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
How do you solve:
3A+2F=240........1
2A+1F=140..............2
1.5A+.5F=100.................3
2 EQNS ARE ENOUGH TO SOLVE..HERE WE HAVE 3..SO SOLVE 2 TO FIND THE UNKNOWNS.THEN SUBSTITUTE THOSE VALUES IN THE OTHER EQN.AND SEE WHETHER THEY ARE CONSISTENT
2*EQN.2-EQN.1
4A+2F-3A-2F=280-240
A=40....SO ...B= 140-2*40=60..
PUTTING IN EQN.3 WE GET
1.5*40+0.5*60=60+30=90...WHICH IS NOT EQUAL TO 100 AS PER EQN.3
HENCE THEY ARE INCONSISTENT,,,HENCE NO SOLUTION
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