# SOLUTION: Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192.

Algebra ->  Algebra  -> Equations -> SOLUTION: Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192.      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Equations Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Equations Question 513184: Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192.Answer by Maths68(1474)   (Show Source): You can put this solution on YOUR website!Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192. Let 1st Interger = x+2 2nd Interger = x+4 3rd Integer = x+6 -4*(1st Integer + 3rd Integer) = 192 -4(x+2+x+6)=192 -4(2x+8)=192 -8x-32=192 -8x=192+32 -8x=224 -8x/-8=224/-8 x=-28 1st Interger = x+2 = -28+2=-26 2nd Interger = x+4 = -28+4=-24 3rd Integer = x+6 = -24+6=-22 Check -4*(1st Integer + 3rd Integer) = 192 -4*(-26 + (-22)) = 192 -4*(-26-22) = 192 -4*(-48) = 192 192=192