SOLUTION: Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192.

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Question 513184: Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192.
Answer by Maths68(1474) About Me  (Show Source):
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Find three consecutive even integers for which -4 times the sum of the first and the third integers is 192.

Let
1st Interger = x+2
2nd Interger = x+4
3rd Integer = x+6
-4*(1st Integer + 3rd Integer) = 192
-4(x+2+x+6)=192
-4(2x+8)=192
-8x-32=192
-8x=192+32
-8x=224
-8x/-8=224/-8
x=-28
1st Interger = x+2 = -28+2=-26
2nd Interger = x+4 = -28+4=-24
3rd Integer = x+6 = -24+6=-22
Check
-4*(1st Integer + 3rd Integer) = 192
-4*(-26 + (-22)) = 192
-4*(-26-22) = 192
-4*(-48) = 192
192=192