SOLUTION: I need a breakdown of the functions (add/multiply/division, etc.) on how to arrive at the solution for the following equation (inequality):
4x + 2 – 6x < -1
I have this compl
Algebra.Com
Question 512468: I need a breakdown of the functions (add/multiply/division, etc.) on how to arrive at the solution for the following equation (inequality):
4x + 2 – 6x < -1
I have this completed process, but i cannot figure out what was done and define each step and how they arrived at the solution:
4x + 2 - 6x < -1
(4x + 6x) + 2 < -1
(4 - 6) x + 2 < -1
-2x + 2 < -1
-2 -2
-2x < -3
-2 -2
x > 3/2
Answer by John10(297) (Show Source): You can put this solution on YOUR website!
Hint: your second step is not correct when you collected the x terms
It should be like below:
4x + 2 - 6x < - 1
(4x - 6x) + 2 < -1
-2x + 2 < - 1
-2x < -1 - 2
-2x < -3
-2x/-2 < -3/-2 (divide both sides by -2)
x > 3/2 (because you divided the NEGATIVE number, you have to change the inequality sign)
The final solution is x > 3/2 or interval is (3/2, inf)
John10:)
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