SOLUTION: Please help me solve this equation: Find the equation of the line perpendicular to -3x+7y=-3 that contains the point (7,6)

Question 511308: Please help me solve this equation:
Find the equation of the line perpendicular to -3x+7y=-3 that contains the point (7,6)
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please help me solve this equation:
Find the equation of the line perpendicular to -3x+7y=-3 that contains the point (7,6)
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Find the slope of the given line:
7y = 3x-3
y = (3/7)x - (3/7)
Its slope is 3/7
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Any perpendicular line must have slope -7/3
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Find equation with slope = -7/3 that passes thru (7,6).
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Form: y = mx + b
6 = (-7/3)(7) + b
6 = -49/3 + b
b = (18/3)+(49/3)
---
b = 67/3
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Equation:
y = (-7/3)x + (67/3)
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Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
First, find the slope of
Get it into the form where
is the slope.

Any line perpendicular to this line will have
slope =

Now use the point-slope formula to find the line
that includes (7,6) and has slope - 7/3

answer
check:
does it contain (7,6)?

OK
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