SOLUTION: Find three consecutive even integers so that 7 times the third is equal to 20 less than the first.

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Question 51060: Find three consecutive even integers so that 7 times the third is equal to 20 less than the first.
Answer by darq(90)   (Show Source): You can put this solution on YOUR website!
Find three consecutive even integers so that 7 times the third is equal to 20 less than the first.
x is the smallest
x + 2 is the medium
x + 4 is the greatest
7 (x + 4) = x - 20
7x + 28 = x - 20
6x = -48
x = -8
#1=-8
#2=-6
#3=-4

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