SOLUTION: solve: x^3-x^2+4*x-4=0 thanks, chris

Question 50682: solve:
x^3-x^2+4*x-4=0
thanks,
chris
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
This is factoring by grouping. Group the first two and last two terms together.

Notice that there is a common factor of (x-1):

or

Are you solving with complex numbers or real numbers only? If real numbers only, then the only answer you have to worry about is x=1. End of problem, since real numbers squared cannot equal a negative.

However, if complex numbers are allowed, then
gives two solutions:
,
, in addition to .

R^2 at SCC

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