# SOLUTION: I am working two-step equations. I understand how to do all but the problems with the fractions in them. Here are two examples. Please tell me if I am doing them right 10=-30 -

Algebra ->  Algebra  -> Equations -> SOLUTION: I am working two-step equations. I understand how to do all but the problems with the fractions in them. Here are two examples. Please tell me if I am doing them right 10=-30 -      Log On

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 Question 50456: I am working two-step equations. I understand how to do all but the problems with the fractions in them. Here are two examples. Please tell me if I am doing them right 10=-30 -c/5 10=-30 -c/5 10=+c-150/5 5*10=-c-150/5 * 5/1 150+20= -c-150+150 200=-c a/5-2=-7 a/5-2+2=-7 a/-5*5/1=-5*-5 a*25 Found 2 solutions by stanbon, tutorcecilia:Answer by stanbon(57361)   (Show Source): You can put this solution on YOUR website!10=-30 -c/5 Add 30 to both sides to get: 40=-c/5 Multiply both sides by 5 to get: 200=-c Multiply both sides by -1 to get: c=-200 ------------- a/5-2=-7 Add 2 to both sides to get: a/5=-5 Multiply both sides by 5 to get; a=-25 --------- Cheers, Stan H. Answer by tutorcecilia(2152)   (Show Source): You can put this solution on YOUR website!10=-30 -c/5 10+30=-30+30 - (c/5) 40=-c/5 (5)(40) = (5)(-c/5) 200=-c 200/-1=-c/-1 -200=c . Check by plugging (-200=c) back into the original equation. 10=-30 -(-200)/5 10=-30 -(-200)/5 10=-30+40 10=10 [checks out] . . a/5-2=-7 a/5-2+2=-7+2 a/5=-5 a/5=-5 (5)(a/5)=(5)(-5) a=-25 . Check by plugging (a=-25) back into the original equation. a/5-2=-7 (-25)/5-2=-7 -5-2=-7 -7=-7 [Checks out]