SOLUTION: If xyz=20, find the value of (6z)(x/2)(12y)
Algebra.Com
Question 497038: If xyz=20, find the value of (6z)(x/2)(12y)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
This is a commutative and associative property problem.
\left(\frac{x}{2}\right)\left(12y\right)\ =\ (6)(z)\left(\frac{1}{2}\right)(x)(12)(y))
(z)\left(\frac{1}{2}\right)(x)(12)(y)\ =\ (6)\left(\frac{1}{2}\right)(12)(x)(y)(z))
\left(\frac{1}{2}\right)(12)(x)(y)(z)\ =\ (6)\left(\frac{1}{2}\right)(12)(xyz))
Now all you have to do is substitute the value you know for 
and do the arithmetic.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
xyz=20 find the value of... (answered by Fombitz)
if X^2+Y^2+Z^2=2(5X-8Y+6Z)-125 THEN FIND THE VALUE OF X+Y+Z... (answered by Edwin McCravy)
Find x the value of... (answered by Fombitz)
If 3x=2y and 5y=6z, what is the value of x in terms of... (answered by Tatiana_Stebko)
x=2z, y=6z what is the value of y=... (answered by sachi)
Solve the folllowing system of linear equations
x-4y+2z=-1
2x+y-3z=10... (answered by Alan3354)
x+y+6z=-31
x+y+9z=-43
x-2y-6z=-26
i have to find out the xyz by eliminating... (answered by lynnlo)
x+y+6z=-31
x+y+9z=-43
x-2y-6z=-26
i have to find out the xyz by eliminating... (answered by lynnlo)
if x + 3y + 2z = 48 and 2x + 3y + 4z = 69, then the value of 3x + 3y + 6z is
(answered by Edwin McCravy)
