SOLUTION: I'm stuck...help. (x/3) - (x/12) = -4 4x - x = -48 3x = -48 x = -16 As I type it now I think I may be correct. Am I? Andrea

Algebra.Com
Question 49534: I'm stuck...help.
(x/3) - (x/12) = -4
4x - x = -48
3x = -48
x = -16
As I type it now I think I may be correct. Am I?
Andrea

Answer by longjonsilver(2297)   (Show Source): You can put this solution on YOUR website!
your method is correct.

To get rid of the fractions in this question we will multiply every term by 12 and then divide the fractions:

(x/3) - (x/12) = -4
12*(x/3) - 12*(x/12) = -4*12
4x - x = -48
3x = -48
x = -48/3
x = -16

CHECK:
(-16/3) - (-16/12)
(-16/3) - (-4/3)
(-16/3) + (4/3)
(-16+4)/3
(-12)/3
-4 --> which is the correct answer, so we KNOW we are correct.

jon.

RELATED QUESTIONS

6(3x-11)-4(3x-1)=8x-12(4-5x) I got 18x-66-12x+4=8x-48+60x 6x-62=68x-48< (answered by MathTherapy)
4x^3+3x^2=64x+48 I tried and ended up with x=16,-16, and -3/4. Is that... (answered by Alan3354)
Help me solve please x^2-3x-12/2x^2-32 multiplied by x^2+8x+16/3x^2+21x+36 This is... (answered by ewatrrr)
a merchant mix peanuts that sells for $3/pound and cashews that sells for $6/pound to get (answered by solver91311,josmiceli)
The question is to simplify the following: ({{{ x^2-4x+4 }}} / {{{ x^2-4 }}}) / ({{{... (answered by richwmiller,Alan3354)
Please help me solve this problem: (x^3 - 13x^2 - 41x + 4) / (x - 7) Right now I have (answered by ewatrrr,DrBeeee)
How do I factor by grouping? 7x^3-28x^2-3x+12 I started by (7x^3-28x^2)+(-3x+12)... (answered by jim_thompson5910)
I have a couple of questions that I am stuck with... (1/4x+3)squared = 48 options... (answered by checkley77)
Express as partial fractions (3x^3+4x^2-12x+16)/(x^4-16) i understand that it is... (answered by Fombitz)