SOLUTION: A projectile is fired from a cliff 100 feet above the water at an inclination of 45° to the horizontal, with a muzzle velocity of 170 feet per second. The height h of the projectil
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Question 471802: A projectile is fired from a cliff 100 feet above the water at an inclination of 45° to the horizontal, with a muzzle velocity of 170 feet per second. The height h of the projectile above the water is given by
h(x)=(-32x^2)/((170)^2)=x=100
where x is the horizontal distance of the projectile from the base of the cliff. How far from the base of the cliff is the height of the projectile a maximum?
A. 225.78 ft
B. 451.56 ft
C. 325.78 ft
D. 777.34 ft
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
You are not posting the equation correctly.
Cheers,
Stan H.
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