# SOLUTION: I need to find 2 equations to the following story problem so I can do the substitution method to solve. How many liters of a 30% alcohol solution must be mixed with 70 liters of a

Algebra ->  Algebra  -> Equations -> SOLUTION: I need to find 2 equations to the following story problem so I can do the substitution method to solve. How many liters of a 30% alcohol solution must be mixed with 70 liters of a       Log On

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 Question 470365: I need to find 2 equations to the following story problem so I can do the substitution method to solve. How many liters of a 30% alcohol solution must be mixed with 70 liters of a 90% solution to get a 50% solution? Can you show me the steps to figure this out. Thanks. Answer by sofiyac(695)   (Show Source): You can put this solution on YOUR website!lets say you need x liters of 30% solution, then y will be the liters of the 50% solution x(30)+70*30=y(50) x+70=y so the two equations are 30x+2100=50y x+70=y solve using substitution