SOLUTION: If a^2 - am + bm + b^2 , what is m in terms of a and b?
A) b - a
B) a - b
C) a + b
D) (a^2 + b^2)/(a - b)
E) (a^2 + b^2)/(a + b)
Thanks!
Algebra.Com
Question 469824: If a^2 - am + bm + b^2 , what is m in terms of a and b?
A) b - a
B) a - b
C) a + b
D) (a^2 + b^2)/(a - b)
E) (a^2 + b^2)/(a + b)
Thanks!
Answer by sofiyac(983) (Show Source): You can put this solution on YOUR website!
I'm assuming equals zero? otherwise we can't solve for m
so the answer is D
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