SOLUTION: What is the real solutions of the equation 3(x+1)^2+16(x+1)+5=0

SOLUTION: What is the real solutions of the equation 3(x+1)^2+16(x+1)+5=0

Algebra.Com

Question 468171: What is the real solutions of the equation 3(x+1)^2+16(x+1)+5=0
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
(3(x+1) + 1)((x+1) + 5) = 0 by direct factoring of the left side.
<==> (3x + 3 + 1)(x + 1 + 5) = 0
<==> (3x + 4)(x + 6) = 0
==> x = -4/3, -6.
RELATED QUESTIONS
find the real solutions of the equation.... (answered by CubeyThePenguin,greenestamps)

What is the sum of the real solutions of the equation (x+1)(x^2 + 1)(x^3 +... (answered by MathLover1,ikleyn)

x^2+5=0 Determinbe the nature of the solutions of the equation. Choose from 2 real... (answered by ewatrrr)

1/x-1 + 1/x+2 = 5/4 Find all real solutions of the... (answered by Nate)

Find all real solutions of the equation (x)square/x-1 + 1/x+2 = 5/4 (answered by Nate)

Find all real solutions of the equation.... (answered by josgarithmetic)

Determine the nature of the solutions of the equation: Does it have 1 real solution, 2... (answered by Alan3354)

Find the real solutions of the radical equation. x^(3/4) - 9[x^(1/4)] =... (answered by josgarithmetic)

Find all real solutions of the given equation.... (answered by richwmiller,Alan3354)