SOLUTION: please solve (6x^2+3x-18)/2x+4

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Question 468030: please solve (6x^2+3x-18)/2x+4
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
(6x^2+3x-18)/(2x+4) = 3x - 9/2
Following is "long division" following the same pattern as all long division

_______________________
2x +4 | 6x^2 +3x -18
- (6x^2 +12x) This is 3x (2x+4)
---------------
-9x - 18
- (-9x - 18) This is -9/2(2x+4)
---------
0
Note:
(2x+4)(3x-9/2) = 6x^2 +3x -18
F First terms 6x^2
O Outside terms -9x
I Inside terms 12x
L Last terms -18

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