SOLUTION: How would I solve the following? x^2+8x= -16 Also the following: 3x^2=2x+5 Thank You

Question 467041: How would I solve the following?
x^2+8x= -16

Also the following:
3x^2=2x+5
Thank You
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2+8x= -16
x^2+8x+16 = 0
(x+4)(x+4) = 0
x = -4 with multiplicity 2
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3x^2=2x+5
3x^2-2x-5 = 0
3x^2-5x+3x-5 = 0
x(3x-5)+ (3x-5) = 0
(3x-5)(x+1) = 0
x = 5/3 or x = -1
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Cheers,
Stan H.
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